*****************
OK, the problem here is a practical one. The "flow outward" this problem wants is in the units kg/sec. Since the density is kg/m^3, and since the vector field v is in m/sec, and since dS has units m^2, the product density*v.dS has units of kg/sec. Thus the rate of flow outward will be
5∫v.dS=5x(8/3)pi
or (40/3)Pi.
Oooh ok that makes sense.
ReplyDeleteCan you help me with Let S be the part of the plane 3x+2y+z=4 which lies in the first octant, oriented upward. Find the flux of the vector field F=1i+1j+4k across the surface S.
ReplyDelete